Question

A ball is launched horizontally off a platform at 15 m/s. The ball takes 1 second to

hit the ground. The height of the platform is
m. The ball will
land
m. from the base of the platform.

Answer 1

Below

Step-by-step explanation:

The ball has one second to fall from its height and to travel horizontally at 15 m/s

Rate X Time = distance 15 m/s * 1 s = 15 meters from the platform .

df = do + vot + 1/2 a t^2

df = final position = o ft ( on the ground)

do = initial position = height

vo = original vertical velocity = 0

a = - 9.81 ms^2

so you have this:

0 = height + 1/2 (- 9.81) m/s^2 * (1)^2

height = 4.9 meters