Answer: Robert has 35 cans of paint - 30 cans of paint that he has already used = 35 - 30 = 5 cans of paint left.
Since each section of trim takes 1/2 can of paint, Robert can paint 2 sections of trim with 1 can of paint.
Therefore, Robert can paint 5 cans of paint * 2 sections of trim per can = 10 sections of trim.
The inequality can be written as 10 <= sections of trim <= 10.
In words, the number of sections of trim that Robert can paint is less than or equal to 10.
On a number line, this solution can be represented as follows:
[9, 10, 11, ...]
^
|
sections of trim
The solution makes sense because Robert has only 5 cans of paint left, so it is not possible for him to paint more than 10 sections of trim.
Explanation: