Answer:
Uncle Mike was 7 times as old as Sally 17 years ago.
Explanation:
Let's call Uncle Mike's current age "x."
Sally is 12 years old, so x = 12 * 3 = 36 years old.
We are looking for years that must pass before Uncle Mike is only twice as old as Sally. So we need to find the age when x = 2 * (12 + n), where n is the number of years that have passed. Solving for n:
36 = 2 * (12 + n)
36 = 24 + 2n
12 = 2n
n = 6
So, six years must pass before Uncle Mike is only twice as old as Sally.
To find out how many years ago Uncle Mike was 7 times as old as Sally, we need to find the age when x = 7 * (12 - m), where m is the number of years ago. Solving for m:
36 = 7 * (12 - m)
36 = 84 - 7m
120 = 7m
m = 17
So, Uncle Mike was seven times as old as Sally 17 years ago.