Question

Find three consecutive integers such that the sum of the first and the third is 8 more than the second number.

Answer 1

Answer: Let's call the first integer "x". Then, the second integer would be x + 1, and the third integer would be x + 2.

According to the problem, the sum of the first and the third integer is 8 more than the second integer:

x + (x + 2) = (x + 1) + 8

Simplifying the left side of the equation:

2x + 2 = x + 9

Subtracting x from both sides:

x + 2 = 9

Subtracting 2 from both sides:

x = 7

So the first integer is 7, the second integer is 8, and the third integer is 9. These are three consecutive integers that satisfy the condition in the problem.

Explanation: