Question

You intend to estimate a population proportion with a confidence interval. The data suggests that the normal distribution is a reasonable approximation for the binomial distribution in this case.

While it is an uncommon confidence level, find the critical value that corresponds to a confidence level of 80.4%.
(Report answer accurate to three decimal places with appropriate rounding.)

Answer 1

Answer: To find the critical value for a 80.4% confidence interval for a normal approximation of a binomial distribution, we need to find the z-score that corresponds to the 80.4% confidence level. We can do this using a standard normal table or using a z-score calculator.

Using a z-score calculator, we can find that the z-score corresponding to 80.4% confidence level is approximately 0.931. This means that 80.4% of the data falls within 0.931 standard deviations of the mean.

So, the critical value that corresponds to a confidence level of 80.4% is approximately 0.931.

Explanation: