Question

Is the value of Y+6 greater in4(y+6)=48 or 12(y+6)=48 how do you know?

Answer 1

To determine which expression has a greater value for Y + 6, we need to isolate Y + 6 on one side of the equation and compare the two expressions.

Starting with 4(y + 6) = 48, we can distribute the 4 to get 4y + 24 = 48. Subtracting 24 from both sides gives us 4y = 24, and then dividing both sides by 4 gives us y = 6. So, for this expression, the value of Y + 6 is 6 + 6 = 12.

Next, for 12(y + 6) = 48, we can distribute the 12 to get 12y + 72 = 48. Subtracting 72 from both sides gives us 12y = -24, and then dividing both sides by 12 gives us y = -2. So, for this expression, the value of Y + 6 is -2 + 6 = 4.

Therefore, the value of Y + 6 is greater in 4(y + 6) = 48 than in 12(y + 6) = 48.

Answer 2

The value of y + 6 is greater in the first equation.

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Divide both sides of the first equation by 4:

• 4(y + 6) = 48
• y + 6 = 12

Divide both sides of the second equation by 12:

• 12(y + 6) = 48
• y + 6 = 4

As we see the first expression has greater value since 12 > 4.