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How much gas (in moles) is in a 20 L container with a pressure of 2 atm at a temperature of 400 K?

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To find the amount of gas in moles, we can use the Ideal Gas Law, which states that PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvin.

Rearranging the equation to solve for n, we get:

n = PV / RT

Plugging in the given values, we get:

n = (2 atm) * (20 L) / (8.31 J/mol*K * 400 K)

Converting atm to Pa:

n = (2 * 101325 Pa) * (20 L) / (8.31 J/mol*K * 400 K)

Converting liters to cubic meters:

n = (2 * 101325 Pa) * (0.02 m^3) / (8.31 J/mol*K * 400 K)

Solving the equation:

n = 0.077 mol

So there are approximately 0.077 moles of gas in the 20-liter container at a pressure of 2 atm and a temperature of 400 K.

User JustinB
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