Question

Hi, can you help me answer this question please, thank you

Answer 1

The margin of error associated with the true population mean is;

`\pm4.652\text{ ounces}`

Step-by-step explanation:

Given the sample size as;

`n=30`

standard deviation as;

`\sigma=13`

the mean;

`\bar{x}=33`

And confidence interval of 95%;

`Z=1.96`

The Margin of Error MOE, can be calculated using the formula;

`\text{MOE}=\pm Z*\frac{\sigma}{\sqrt[]{n}}`

Substituting the given values;

`\text{MOE}=\pm1.96*\frac{13}{\sqrt[]{30}}=\pm4.652`

Therefore, the margin of error associated with the true population mean is;

`\pm4.652\text{ ounces}`