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Perform the indicated operations. x-2 x+3 x + ¹ + 3y 4y 6 y O x-4 y 09x-8 12y 5x-8 12y Perform the indicated operations . x - 2 x + 3 x + ¹ + 3y 4y 6 y O x - 4 y 09x - 8 12y 5x - 8 12y

Perform the indicated operations. x-2 x+3 x + ¹ + 3y 4y 6 y O x-4 y 09x-8 12y 5x-8 12y-example-1
User Noah May
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1 Answer

14 votes
14 votes

Given:


(x+1)/(3y)+(x-2)/(4y)-(x+3)/(6y)

To solve it, follow the steps below.

Step 01: Find a common denominator.

Factoring the coefficients:

3, 4, 6 | 2

3, 2, 3 | 2

3, 1, 3 | 3

1, 1 ,1

2*2*3 = 12

The common denominator can be 12y.

Step 02: Write the function using the common denominator.


\begin{gathered} (x+1)/(3y)+(x-2)/(4y)-(x+3)/(6y) \\ (4*(x+1)+3(x-2)-2(x+3))/(12y) \end{gathered}

Step 03: Solve the function.


\begin{gathered} (4*x+4*1+3*x+3*(-2)-2*x-2*3)/(12y) \\ (4x+4+3x-6-2x-6)/(12y) \end{gathered}

Adding the like-terms.


\begin{gathered} (4x+3x-2x+4-6-6)/(12y) \\ (5x-8)/(12y) \end{gathered}

Answer:


(5x-8)/(12y)

User Jonah Graham
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