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The length of a new rectangular playing field is 7 yards longer than double the width. If the perimeter of the rectangular

playing field is 260 yards, what are its dimensions?

User Muki
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2 Answers

4 votes

Final answer:

To find the dimensions of the playing field, we set up equations with the given relationships: the length is twice the width plus 7 yards, and the perimeter is 260 yards. Solving these, we find the width to be 41 yards and the length to be 89 yards.

Step-by-step explanation:

To find the dimensions of a rectangular playing field where the length (L) is 7 yards longer than double the width (W), and the perimeter (P) is 260 yards, we will set up equations using the given information:

  • L = 2W + 7
  • P = 2L + 2W

Plugging in the first equation into the second, we have:

  • 260 = 2(2W + 7) + 2W
  • 260 = 4W + 14 + 2W
  • 260 = 6W + 14
  • 246 = 6W
  • W = 41 yards

Now that we have the width, we can find the length:

  • L = 2(41) + 7
  • L = 82 + 7
  • L = 89 yards

The dimensions of the playing field are 89 yards in length and 41 yards in width.

User MrDrews
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6.6k points
4 votes

Answer:

Step-by-step explanation:

6w + 18 = 330

18 -18

6w = 312

6 6

w = 52 yards, which is the width.

l = 2(52) + 9 = 113 yards, which is the length.

User Ryan Shannon
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7.3k points