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The same art teacher estimates that he has enough clay for 9 students. Is he correct? Why?

Remember: He has 47 1/3 pounds of clay and wants to give each student 2 1/2 lbs of clay.

*Use compatible numbers to estimate. These are numbers that are close to the actual numbers that you know will divide easily.

1 Answer

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Answer:

The art teacher is incorrect.

Explanation:

Coming Up with Compatible Estimate Numbers:

The teacher has 47 1/3 pounds of clay. We can round this to 50. Now we have 50 pounds of clay.

Explaining the Operations:

The teacher wanted to distribute the clay by 2.5 lbs. This means we need to divide the amount of clay by 2.5.

Performing the Operations:

Divide 50 by 2.5 ---> 50÷2.5=(5÷2.5)*10--->5÷2.5=2--->2*10=20

Final Conclusion

For every student, the art teacher plans to give 2.5 lbs of clay. This means he will divide his 47 1/3 pounds by 2.5 piles and hand them out to the students. If we round 47 1/3 to 50 (about 2 points higher) and divide 50 by 2.5, you get 20. This means he would have a little less than enough clay for 20 students, not 9. Therefore, the art teacher is incorrect.

****ANOTHER POSSIBLE SOLUTION****

You can also multiply 9 x 2.5 and see if the product is close to 47 1/3. In this case, you can round 2.5 to 3 and proceed with the multiplication. 9*3=27 Since 27 is a lot lower than 47 1/3, the art teacher is incorrect.

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