Question

tom's age is $t$ years, which is also the sum of the ages of his three children. his age $n$ years ago was twice the sum of their ages then. what is $t/n$?

Answer 1

t/n = 5

Explanation:

Now:

Let t = Tom's age now.

Let s = sum of children's ages now.

n years ago:

Tom's age = t - n

Each of the three children was n years younger, so the sum of their ages n years ago is s - 3n

t = s

t - n = 2(s - 3n)

t = s

t - n = 2(t - 3n)

t = s

t - n = 2t - 6n

t = s

-t = -5n

-t/n = -5

t/n = 5