25.2k views
4 votes
In circle K with m \angle JKL= 48m∠JKL=48 and JK=10JK=10 units find area of sector JKL. Round to the nearest hundredth

User OShadmon
by
7.6k points

1 Answer

5 votes

Answer:

41.89 square units

Explanation:

You want the area of 48° sector JKL in circle K of radius 10 units.

Area

The area of a sector is given by the formula ...

A = 1/2r²θ

where r is the radius and θ is the central angle in radians.

Application

The radian measure of an angle of 48° can be found by multiplying it by (π/180°). Here, we have ...

θ = 48° = (48°)(π/180°) radians = 4π/15 radians

Then the area is ...

A = 1/2(10²)(4π/15) = 40π/3 ≈ 41.89 . . . . square units

The area of sector JKL is about 41.89 square units.

<95141404393>

In circle K with m \angle JKL= 48m∠JKL=48 and JK=10JK=10 units find area of sector-example-1
User Keveman
by
7.5k points