Question

NEED VERY FAST

An aircraft is landing on an aircraft carrier. The aircraft’s mass is 17,600 kg. Assume its initial horizontal landing speed is 66 m/s.

What is the magnitude of the force that the arresting wire exerts on the aircraft, assuming that the aircraft’s deceleration is uniform?


An aircraft is landing on an aircraft carrier. The aircraft’s mass is 17,600 kg. Assume its initial horizontal landing speed is 66 m/s.

What is the aircraft’s deceleration if it stops 1.6 s after catching the arresting wire with its tailhook?

Answer 1

The magnitude of force that the arresting wire exerts on the aircraft is 726,000N.

The aircraft's deceleration, if it stops 1.6s after catching the arresting wire with its tailhook is 41.25m/s².

We know that force is:

F = |ma| ... (i)

where, F ⇒ magnitude of force

m ⇒ mass

a ⇒ acceleration

We also know that acceleration is:

a = (v-u)/t ... (ii)

where, a ⇒ acceleration

v ⇒ final velocity

u ⇒ initial velocity

As per the question,

Mass of aircraft, m = 17,600kg

Initial velocity, u = 66m/s

Final velocity, v = 0m/s

Time, t = 1.6s

Now, putting the values in equation (ii),

a = (0-66)/1.6

a = -41.25m/s²

Now putting the values in equation (i),

F = |17600 × (-)41.25|

F = 726,000N

Therefore, the magnitude of force that the arresting wire exerts on the aircraft is 726,000N and the aircraft's deceleration, if it stops 1.6s after catching the arresting wire with its tailhook is 41.25m/s².