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What is the greatest value of 2n+7 when 7/12 ≥ 5/6+n

User JakubKnejzlik
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2 Answers

9 votes
9 votes

Answer:

7k+1−2k+1⋮5⇔((7k+1−2k+1)−(7k−2k))⋮5

((7k+1−2k+1)−(7k−2k))=7⋅7k−2⋅2k−7k+2k=

=6⋅7k−2k=5⋅7k+(7k−2k)⋮5

5⋅7k⋮5

(7k−2k)⋮5

User Supertrue
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19 votes
19 votes
(7k-2K):5

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User Csbarnes
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