Question

The decomposition of potassium chlorate (KClO3) is used as a source of oxygen in the laboratory. How much potassium chlorate is needed to produce 19.4 mol of oxygen?

Answer 1

Answer: 6.47 moles of (KClO3) will be needed

Step-by-step explanation:

There are 3 atoms of oxygen in each potassium chlorate molecule.

divide the desired number of moles of oxygen by three and you have your answer.