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The decomposition of potassium chlorate (KClO3) is used as a source of oxygen in the laboratory. How much potassium chlorate is needed to produce 19.4 mol of oxygen?

User Yehudit
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1 Answer

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Answer: 6.47 moles of (KClO3) will be needed

Step-by-step explanation:

There are 3 atoms of oxygen in each potassium chlorate molecule.

divide the desired number of moles of oxygen by three and you have your answer.

User Keeda
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