Between 87 and 81 looks a bit suspicious, I don’t know if you’re missing a sign or not, but if not, it’ll just be multiplication. So let’s write the problem but with parentheses to understand it better:
27√((81)+(87^2)(81^3))
First, let’s write 27 in exponential form:
3^3√((81)+(87^2)(81^3))
Next, evaluate the power for 87^2:
3^3√((81)+(7569)(81^3))
Next, we will factor inside the parentheses:
3^3√((81((1)+(7569)(81^2)))
Next, we will evaluate the power for 81^2:
3^3√((81((1)+(7569)(6561)))
Next, multiply 7569 and 6561:
3^3√((81((1)+(49660209)))
Next, add one to 49660209:
3^3√(81(49660210))
Next, because the square root of 81 is 9, we will write it in exponential form because the base will be 3 as well:
(3^3)(3^2)√(49660210)
Next, multiply 3^2 and 3^3. When they have the same base, simply keep the base and add the exponents:
3^5√(49660210)
Now evaluate the power for 3^5:
243√(49660210)
That’s your answer! Or it can be written as 1.71242x10^6.
Hope this helped!