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How many atoms are in 35 grams of sucrose, C12H22O11?

How many atoms are in 35 grams of sucrose, C12H22O11?-example-1
User Ggilberth
by
8.5k points

2 Answers

3 votes

Answer:

There are approximately 6.18 x 10^22 atoms in 35 grams of sucrose. So option
C) 6.15 x 10^22 atoms

Step-by-step explanation:

To determine the number of atoms in a given amount of a substance, you would need to know its molecular weight and use Avogadro's number.

The molecular weight of sucrose (C12H22O11) can be calculated as follows:

12 carbon atoms x 12 g/mol/atom = 144 g/mol

22 hydrogen atoms x 1 g/mol/atom = 22 g/mol

11 oxygen atoms x 16 g/mol/atom = 176 g/mol

Total molecular weight of sucrose = 342 g/mol

Therefore, 35 grams of sucrose contains 35 g / 342 g/mol = 0.102 moles of sucrose.

Using Avogadro's number (6.022 x 10^23 atoms/mole), we can find the number of atoms in 35 grams of sucrose:

0.102 moles x 6.022 x 10^23 atoms/mole = 6.18 x 10^22 atoms.

So, there are approximately 6.18 x 10^22 atoms in 35 grams of sucrose.

User Geoherna
by
8.6k points
3 votes

Hello!

Answer:

12 carbon atoms, 22 hydrogen atoms and 11 oxygen atoms.

Hope this helps!

User Thomas Wang
by
8.7k points
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