Answer:
There are approximately 6.18 x 10^22 atoms in 35 grams of sucrose. So option
C) 6.15 x 10^22 atoms
Step-by-step explanation:
To determine the number of atoms in a given amount of a substance, you would need to know its molecular weight and use Avogadro's number.
The molecular weight of sucrose (C12H22O11) can be calculated as follows:
12 carbon atoms x 12 g/mol/atom = 144 g/mol
22 hydrogen atoms x 1 g/mol/atom = 22 g/mol
11 oxygen atoms x 16 g/mol/atom = 176 g/mol
Total molecular weight of sucrose = 342 g/mol
Therefore, 35 grams of sucrose contains 35 g / 342 g/mol = 0.102 moles of sucrose.
Using Avogadro's number (6.022 x 10^23 atoms/mole), we can find the number of atoms in 35 grams of sucrose:
0.102 moles x 6.022 x 10^23 atoms/mole = 6.18 x 10^22 atoms.
So, there are approximately 6.18 x 10^22 atoms in 35 grams of sucrose.