Question

(20 POINTS) Perfect Pizza has 15 toppings listed on their menu. How many ways could a customer choose a pizza that contains 3 different toppings?

18
45
455
910


EXPLANATION WILL HELP ASWELL

Answer 1

The answer is 455 ways

Explanation:

If adding only twelve, you must leave out three of the fifteen, and the number of ways is: = 15! / (3! * 12!).1∗2∗3∗4∗5∗6∗6∗8∗9∗10∗11∗12∗13∗14∗15 over(1∗2∗3)∗(1∗2∗3∗4∗5∗6∗6∗8∗9∗10∗11∗12) =13∗14∗15 over(1∗2∗3) 27306 = 455

Or:15! / (3! * 12!) = 455.

Best of Luck to you! I hope this helps you.

Answer 2

The number of ways a customer could choose a pizza that contains 3 different toppings is 455

Explanation:

A customer could choose a pizza that contains 3 different toppings in C(15,3) ways, which is the number of combinations of 15 items taken 3 at a time.

The formula for combinations is given by:

C(n,k) = n! / (k! (n-k)!)

where n! means n factorial, which is the product of all positive integers from 1 to n.

Plugging in n = 15 and k = 3:

C(15,3) = 15! / (3! (15-3)!) = 15! / (3! 12!)

Using a calculator, we find that:

C(15,3) = 455

So, the number of ways a customer could choose a pizza that contains 3 different toppings is 455. The answer is 455.