Question

A car is moving with a speed of 29.8 m/s. The driver sees an accident ahead and slams on the brakes, giving the car a "deceleration" of 3.1 m/s 2. How far (in meters) does the car travel after the driver put on the brakes before it comes to a stop?

Answer 1

143.2 m

Step-by-step explanation:

Final speed is 0, initial speed is 29.8 m/s, a = -3.1 m/s²

v² = v₀² + 2aΔx

0 = (29.8 m/s)² + 2(-3.1 m/s²)(Δx)

Δx = -(29.8 m/s)² / 2(-3.1 m/s²) = -888 m²/s² / -6.2 m/s² = 143.2 m