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Emma has money in two savings accounts. One rate is 12% and the other is 13%. If she has $950 more in the 13% account and the total interest is $194, how much is invested in each savings account?

User Adityaatri
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2 Answers

1 vote

Final answer:

Emma has $282 in the 12% savings account and $1232 in the 13% savings account. The problem is solved by setting up a system of linear equations based on the given interest rates and total interest earned.

Step-by-step explanation:

To solve the problem involving Emma's savings accounts with different interest rates, we'll use a system of linear equations. Emma has two bank accounts, one with an interest rate of 12% and the other with an interest rate of 13%. If she has $950 more in the 13% account than the 12% account, and the total interest from both accounts is $194, we need to determine the amount invested in each account.

Let's denote the amount in the 12% account as x and the amount in the 13% account as x + $950. The total interest (I) earned is $194. We can now express the total interest earned from each account as follows:

  • Interest from 12% account: 0.12x
  • Interest from 13% account: 0.13(x + $950)

The equation that represents the total interest from both accounts is:

0.12x + 0.13(x + $950) = $194

This simplifies to:

0.12x + 0.13x + $123.5 = $194

Combining like terms, we get:

0.25x = $70.5

Dividing both sides by 0.25:

x = $282

Therefore, Emma has $282 in the 12% account and $1232 (282 + $950) in the 13% account.

User Jooyoun
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7.4k points
3 votes

SI=PxR/100xT

$194= $950x13/100=0.13

=$23959

User Sheldon Fernandes
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7.4k points