Question

PLEASE HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Can somebody please explain to me how to solve this?At this point I am just guessing the answers. thank you!!!!!!!!!!!!

Answer 1

Check the picture below.

so let's take the area for the whole containing rectangle, well, the rectangle is a 21x10, so just that product is it, and then let's get the area of the green triangle there, if we subtract the area of the triangle from the whole rectangle, we're in effect making a hole in the rectangle, and what's leftover is, you guessed it, the shaded area.

`\stackrel{\textit{\LARGE Areas}}{\stackrel{rectangle}{(21)(10)}~~ - ~~\stackrel{triangle}{\cfrac{1}{2}(\underset{b}{21})(\underset{h}{10})}}\implies 210-105\implies \text{\LARGE 105}~yd^2`

Answer 2

To find the area of the shaded region, find the area of the rectangle along with the area of the triangle that is enclosed by the rectangle.

Area of Rectangle=Lw
=> 21*10=210 yd^2

Area of Triangle=(1/2)bh
=(1/2)*21*10=105 yd^2

Area of the shaded region=(Area of Rectangle)-(Area of Triangle)

=>210-105=105


Thus the area of the shaded region is 105 yd^2