Question

A gas has a pressure of 1.15 atm and occupies a volume of 6.5 L. If the gas is compressed to a volume of 1.11 L, what will its pressure be,

assuming constant temperature? Answer in units of atm.

Answer 1

with sig figs, 6.73atm

without, 6.73423423

Step-by-step explanation:

We can use Boyle's law because we're given two volumes, and one pressure.

P1V1 = P2V2

plug the numbers your given into the equation:

(1.15atm)(6.5L) = P2(1.11L)

Then just solve it like an alegbra 1 problem.

7.475atmL/1.11L = P2

units of liters cancel when dividing.

6.73423423atm = P2

using the sig figs of the original pressure, you get 6.73atm.

:)