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What is an equation of the line that passes through the point (-8,0)(−8,0) and is parallel to the line x+2y=14x+2y=14?

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To find an equation of the line that passes through the point (-8, 0) and is parallel to the line x + 2y = 14, we can use the slope-point form of the equation of a line: y - y1 = m(x - x1), where (x1, y1) is a point on the line, m is the slope of the line, and y and x are the variables.

First, we need to find the slope of the line x + 2y = 14. We can rearrange this equation into slope-intercept form: y = -(1/2)x + 7. The slope of the line is -1/2.

Since the line we're looking for is parallel to x + 2y = 14, it must have the same slope, which is -1/2. We can now use the point-slope form to write the equation of the line that passes through (-8, 0) and has slope -1/2: y - 0 = -1/2 (x - (-8)). Simplifying, we get: y = -1/2x + 4.

So, an equation of the line that passes through the point (-8,0) and is parallel to the line x + 2y = 14 is y = -1/2x + 4.
User AxelEckenberger
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