Question

4. Consider the circuit shown in the figure below.

Find:
(a) the voltage across the 3 resistor.
(b) the current in the 4 Q2 resistor.
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Answer 1

Resistance of 5 & 10 in parallel

R510 = (5 * 10) / 15 = 3.33 ohms

Adding 4 + 3.33 = 7.33 ohms

This is in parallel with 3 ohms giving

(7.33 * 3) / (7.33 + 3) = 2.13 ohms for combination

Now (2 + 2.13) = 4.13 for upper half of circuit

8 / 4.13 = 1.94 amps in circuit

1.94 * 2 = 3.88 across 2 ohm resistor

8 - 3.88 = 4.12 across the 3 ohm resistor

I'm not sure what you mean by the 4 Q2 resistor