Answer:
diameter = 16
Explanation:
given AB is a tangent to the circle then ∠ PBA = 90° and Δ ABP is right
using Pythagoras' identity in the right triangle
BP² + AB² = AP²
BP² + 15² = 17²
BP² + 225 = 289 ( subtract 225 from both sides )
BP² = 64 ( take square root of both sides )
BP =
= 8
now BP is the radius of the circle , so
diameter = 2 × BP = 2 × 8 = 16