Answer:
The probability that the height of a randomly selected tree is as tall as mine or shorter.
P(X≤182.2) = 0.0082
Explanation:
Step(i):-
Mean of the Population = 191.8 ft
Standard deviation of the Population = 4 ft
Let 'X' be the random variable in normal distribution
X = 182.2 feet


Step(ii):-
The probability that the height of a randomly selected tree is as tall as mine or shorter.
P(X≤182.2) = P( z≤ -2.4)
= 1-P(z>2.4)
= 1-(0.5 + A(2.4))
= 0.5 - A(2.4)
= 0.5 - 0.4918
= 0.0082
The probability that the height of a randomly selected tree is as tall as mine or shorter.
P(X≤182.2) = 0.0082