Question

Question 2

The sum of Eli's age and Cecil's age is 60. Six years ago, Eli was three times as
old as Cecil.Find Eli's age now.

Answer 1

Eli is 42 and Cecil is 18

Explanation:

Let e = Eli's age

Let c = Cecil's age

e + c = 60 ⇒ e = 60 - c

(e-6) = 3(c - 6) We subtract 6 from their age to show that is was 6 years ago.

e - 6 = 3c - 18 Distribute the 3

Substitute 60 - c for e into the second equation

60 - c - 6 = 3c - 18 Combine like terms

54 - c = 3c - 18 Add c to both sides

54 = 4c - 18 Add 18 from both sides

72 = 4c Divide both sides by 4

c = 18

Cecil is 18

e + c = 60 Substitute 18 for c to solve for Eli's age

e + 18 = 60 Subtract 18 from both sides

e = 42

Eli is 42

Answer 2

Below

Explanation:

e = eli's age NOW six years ago it was e -6

c = cecil's age NOW six years ago it was c - 6

Given e+c = 60 and

(e-6) = 3 ( c-6) From the first equation c = 60-e

e-6 = 3 ( 60-e -6) expand R side

e -6 = 180 - 3e - 18 simplify

4e = 168

e = 42 y/o