Question

What is the equation of the line that passes through thé point (-1, 3) and has a
slope of -3?

Answer 1

Answer: y=-3x+6

Explanation:

The equation for slope intercept form is y=mx+b, and since you are given your y and x values from the point (-1, 3), you can plug those values into it. You are also given your slope of -3, and since m is your slope value, you would plug the -3 in as your m.

After you plug in your given values from the problem, you should should get 3 = -1 (3) + b.

Then, you isolate the b. Multiply the -1 and 3 to get -3.

3 = -1 (3) + b

3 = -3 + b

Next, add the 3 to both sides of the equation, and you should be left with b=6.

3 = -3 + b

+3 +3

--------------

6 = 0 + b

6 = b

Finally, you re-write the slope intercept equation with the y-intercept (b value) you just found along with the slope of -3 given by the problem to get y=-3+6.

Answer 2

The equation of a line in slope-intercept form is given by y = mx + b, where m is the slope of the line and b is the y-intercept.

To find the equation of the line that passes through the point (-1, 3) and has a slope of -3, we can use the point-slope form of a line: y - y1 = m(x - x1), where m is the slope of the line and (x1, y1) is a point on the line.

Substituting the given values, we get: y - 3 = -3(x - (-1))

Expanding the right side, we get: y - 3 = -3x + 3

Adding 3 to both sides, we get: y = -3x + 6

So the equation of the line that passes through the point (-1, 3) and has a slope of -3 is y = -3x + 6.

Hope this helps,

- Jeron :- )