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Divide using long division. (9x^3-18x^2-x+2) /(3x+1)

User Xipooo
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Answer: To divide 9x³ - 18x² - x + 2 by 3x + 1 using long division, we can follow the following steps:

Step 1: Divide the first term of the dividend 9x³ by the first term of the divisor 3x. The result is 3x².

Step 2: Multiply the divisor 3x + 1 by 3x². The result is 9x³ + 3x².

Step 3: Subtract 9x³ + 3x² from 9x³ - 18x² - x + 2. The result is -18x² - 4x + 2.

Step 4: Repeat the division and multiplication process by dividing the first term of the new dividend, -18x², by the first term of the divisor, 3x. The result is -6x.

Step 5: Multiply the divisor 3x + 1 by -6x. The result is -18x + 6.

Step 6: Subtract -18x + 6 from -18x² - 4x + 2. The result is -4x² + 10.

Step 7: Repeat the division and multiplication process by dividing the first term of the new dividend, -4x², by the first term of the divisor, 3x. The result is -4/3 x.

Step 8: Multiply the divisor 3x + 1 by -4/3 x. The result is -4/3 x + 4/3.

Step 9: Subtract -4/3 x + 4/3 from -4x² + 10. The result is 10 - 4/3.

Thus, the final answer is:

(9x³ - 18x² - x + 2) / (3x + 1) = 3x² - 6x - 4/3 x + 4/3 + 10

Explanation:

User Knowleech
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