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A ball is dropped from 10 feet above the ground. The function h (t) = -16 t² + 10, where t represents the time

in seconds, h gives the height, in feet, of the ball above the ground. When will the ball be 4 feet above the ground? Use
the given quadratic function model to answer questions about the situation it models.

User Istiaque
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Answer: The equation to find the time when the ball is 4 feet above the ground is:

-16t^2 + 10 = 4

We can solve for t by subtracting 4 from both sides:

-16t^2 + 6 = 0

And then dividing both sides by -16:

t^2 = -6 / -16

t^2 = 3/8

Taking the square root of both sides:

t = ±√(3/8)

Since time cannot be negative, we choose the positive solution:

t = √(3/8)

So the ball will be 4 feet above the ground after √(3/8) seconds.

Explanation:

User Puteri
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