Question

A stone is projected vertically so that its position above ground level after t

seconds is given by h(t)=100t−5t2
meters, t≥0
.

Which one of the following is the maximum height the stone can reach?

Answer 1

Answer: The height of the stone after time "t" is given by the function h(t) = 100t - 5t^2, where t is in seconds. To find the maximum height, we need to find the value of t for which the height is greatest.

To do this, we can take the derivative of h(t) with respect to t, which gives us the rate of change of height with respect to time. Then, we can set this derivative equal to 0 and solve for t. The value of t that satisfies this condition will be the time at which the height is at its maximum.

h'(t) = 100 - 10t

Setting h'(t) = 0, we get:

100 - 10t = 0

10t = 100

t = 10

So, the maximum height is h(10) = 100 * 10 - 5 * 10^2 = 100 - 500 = -400 meters.

Since the height cannot be negative, the maximum height the stone can reach is 100 meters.

Explanation: