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6. Given f(x)=3x² - 2x+4, find a. ƒ(-2)= b. f(k+1)=​

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Answer: a. To find f(-2), substitute -2 for x in the function f(x):

f(-2) = 3(-2)² - 2(-2) + 4 = 3(4) - 2(-2) + 4 = 12 - (-4) + 4 = 16

So, f(-2) = 16.

b. To find f(k+1), substitute (k+1) for x in the function f(x):

f(k+1) = 3(k+1)² - 2(k+1) + 4 = 3k² + 6k + 3 - 2k - 2 + 4 = 3k² + 4k + 5

So, f(k+1) = 3k² + 4k + 5.

Explanation:

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