Question

A quadratic function has the equation, y=a(x+3)(x−5) = ( x+3)( x−5), and passes through the point (6,45). What is the value of a ?

Answer 1

Explanation:

To find the value of "a" in the equation y = a(x + 3)(x - 5), we can use the fact that the function passes through the point (6, 45).

Step 1: Substitute the x and y values of the point into the equation:

45 = a(6 + 3)(6 - 5)

45 = a(9)(1)

Step 2: Solve for "a":

45 = 9a

a = 45/9

a = 5

The value of "a" in the equation y = a(x + 3)(x - 5) is 5.