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Enter a quadratic polynomial which has zeros -8 and 10

User Justin Fay
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2 Answers

15 votes
15 votes

Answer: y = x^2-2x-80

Explanation:

y = (x+8)(x-10) (set the zeros equal to a factor)

y = x^2-2x-80

User Raghu Ariga
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2.9k points
12 votes
12 votes

Answer:

y = x² - 2x - 80

Explanation:

given a polynomial with zeros x = a and x = b , then the factors are

(x - a) and (x - b)

the polynomial is then the product of the factors, that is

y = (x - a)(x - b)

given zeros x = - 8 and x = 10, then the factors are

(x - (- 8) ) and (x - 10) , that is (x + 8) and (x - 10)

the polynomial is then

y = (x + 8)(x - 10) ← expand factors using FOIL

y = x² - 2x - 80

User Mwigdahl
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2.7k points