Question

The polygon in the diagram is a square with center P. The length from the center to the vertex is 6sqrt(2) in. Find the area of the square to the nearest tenth of an inch.

A) 24.0 in^2
B) 72.0 in^2
C) 36.0 in^2
D) 144.0 in^2

Answer 1

Since the length from the center to the vertex is 6sqrt(2) in, then half of that is 6sqrt(2)/2 = 3sqrt(2) in, which is the side length of the square. To find the area, we can square the side length:

Area = (3sqrt(2))^2
Area = 9 * 2
Area = 18

So the answer is 18 in^2, and rounded to the nearest tenth, the area of the square is 18.0 in^2, which corresponds to option C: 36.0 in^2.