Question

A light bulb that has a resistance of 3 Ω is connected to a 9 V battery.

What current will the bulb draw? A. 1/3 A B. 3 A C. 6 A D. 12 A E. 27 A
What is the bulb’s power? A. 1/3 W B. 3 W C. 6 W D. 12 W E. 27 W

Answer 1

see below

Step-by-step explanation:

We have ,

• R = 3Ω
• V = 9V

So , from V = iR ,

i = V/R

i = 9/3 A

i = 3A [ option B ]

again, we know that, Power = v²/R , so ;

P = 9²/3 W

P = 27W [ option E ]

and we are done!