Question

Jaelyn had $150 in the school account and sold tickets for the fundraiser at a cost of

58 per ticket. Erik had $480 in his school account and sold tickets for $6 per ticket. How many tickets had to be sold before both accounts had the same amount of money?

Answer 1

Let x be the number of tickets sold.

Jaelyn's account balance after selling tickets: 150 + 58x

Erik's account balance after selling tickets: 480 + 6x

For both accounts to have the same amount, we set their balance equal to each other and solve for x:

150 + 58x = 480 + 6x

52x = 330

x = 330/52 = 6.25

So 6.25 tickets had to be sold before both accounts had the same amount of money.