Question

Use the following data to calculate the Ksp value for each solid.a. The solubility of CaC2O4 is 6.1 × 10−3 g/L.b. The solubility of BiI3 is 1.32 × 10−5 mol/L.

Answer 1

The Ksp value for CaC2O4 is 2.54 × 10-9 and for BiI3 is 3.669 × 10-33.

Step-by-step explanation:

The Ksp value can be calculated using the solubility data provided. For CaC2O4, the concentration of Ca²+ and ox²- ions is both 5.04 × 10-5 M. Plugging these values into the solubility product expression, Ksp = [Ca²+][ox²-] = (5.04 × 10-5)(5.04 × 10-5) = 2.54 × 10-9.

Similarly, for BiI3, the solubility is 1.32 × 10-5 mol/L. Since BiI3 dissociates into Bi³+ and I- ions in a 1:3 ratio, the concentration of Bi³+ is (1.32 × 10-5)(1/4) = 3.3 × 10-6 M, and the concentration of I- is (1.32 × 10-5)(3/4) = 9.9 × 10-6 M. Plugging these values into the solubility product expression, Ksp = [Bi³+]1[I-]3 = (3.3 × 10-6)(9.9 × 10-6)3 = 3.669 × 10-33.