Answer:
d) (n = 3, 1 = 1, mi = -1)
Step-by-step explanation:
A 3p orbital must have n = 3.
That eliminates Option (a), because it has n = 1.
A p orbital must have I = 1.
That eliminates Options (b), (c), and (e), because
they have I = 3, 2, and O.
The only correct option is
n = 3, 1=1, mi =-1