Answer:
(d) C'(-1, 14)
Explanation:
You want the coordinates of C' after the point C(-1, -6) is reflected across the line y = 4.
Reflection
Reflection across the horizontal line y=4 will not change the x-coordinate of the point, so C' has an x-coordinate of -1.
The point (-1, 4) on the line of reflection will be the midpoint of C and C', so we have ...
(C +C')/2 = (-1, 4)
C +C' = 2(-1, 4) = (-2, 8) . . . . .multiply by 2
C' = (-2, 8) -C
C' = (-2, 8) -(-1, -6) = (-1, 8+6)
C' = (-1, 14)
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Additional comment
Effectively, the reflection across the line y=4 is the transformation ...
(x, y) ⇒ (x, 8 -y)