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If the coefficient of kinetic friction is 0.43 for a box sliding across your lab table and the box weighs 7.4 N, what is the force of kinetic friction?
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If the coefficient of kinetic friction is 0.43 for a box sliding across your lab table and the

box weighs 7.4 N, what is the force of kinetic friction?

User Caleb Prenger
by
2.9k points

1 Answer

6 votes

Answer:

3.2N

Step-by-step explanation:

Given parameters:

Coefficient of kinetic friction = 0.43

Weight of box = 7.4N

Unknown:

Force of kinetic friction = ?

Solution:

The force of kinetic friction is given as:

Force of kinetic friction = UN

U is the coefficient of friction

N is the weight

Force of kinetic friction = 0.43 x 7.4 = 3.2N

User Geon George
by
3.1k points
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