Question

In 1994, the city of Amuel had a population of 1,256 people. That same year a factory opened near the town, and many people moved into the city limits. The population grew to 1,381 people in 1995, and in 1996 the population of Amuel reached 1,519 people. Assume this rate of growth continued until the factory closed in 2007. How many people were living in Amuel when the factory closed? Explain. Round to the nearest whole number, if needed.

Answer 1

4604 (when rounded to the nearest whole number)

Step by step explanations:

Using the exponential growth formula, we can determine Amuel's population at the time the factory shut down: N = N0 * e^(rt) (rt) Where r is the growth rate, t is the number of years the growth takes place, N is the ultimate population, N0 is the starting population, and r represents growth.

We may use the population data from 1995 and 1996 to get the growth rate: r = ln(1,381 / 1,256) / (1996 - 1995) (1996 - 1995)

Putting the numbers in: r = 0.117

Next, we determine how many years the growth took place: t = 13 years (2007 - 1994) Lastly, we enter the values into the formula as follows: N = 1,256 * e^(0.117 * 13)

Calculating the answer, we discover: 4,604 persons (N = 1,256 * 3.63) Consequently, there were about 4,604 residents there when the facility shut down in 2007.