Question

what is the force exerted by a catchers glove on a .15 kg baseball moving at 35 m/s that is stopped in .02 s

Answer 1

Step-by-step explanation:

v=u+at

Final velocity v=0 , u=35m.s, a=-a , t=0.02

a=u/t = 35/0.02 = 1750 m/s2

force = mass * acceleration = 0.15 * 1750 = 262.5N