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a baseball is thrown straight up at a speed of 30.0 m/s. at what time will the ball be at a height of 25.0 m?

1 Answer

2 votes

Answer:

t = 0.995 s, 5.127 s

Step-by-step explanation:

Δx = v₀t + 1/2at²

25.0 m = (30 m/s)t + 1/2(-9.8 m/s²)t²

-4.9t² + 30t - 25 = 0 solve this quadratic equation for t (2 solutions)

t = 0.995 s, 5.127 s

It reaches a height of 25 m in 0.995 s, then again 5.127 s later on its way back down

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