Question

What is the current flowing through this circuit?

A) 1.3 A
B) 6.7 A
C) 15 A
D) 0.15 A

Answer 1

see below

Step-by-step explanation:

the given circuit comprises of a 10V battery and 2Ω and 6Ω resistance. The resistances are connected in parallel, so we can find the net resistance as ,

`\implies (1)/(R_n)=(1)/(R_1)+(1)/(R_2) \\`

`\implies R_n =(R_1R_2)/(R_1+R_2) \\`

`\implies R_n =(2* 6 )/(2+6)\Omega \\`

`\implies R_n =(12)/(8)\Omega\\`

`\implies R_n = 1.5\Omega \\`

Now from Ohm's law, we have,

`\implies V = iR \\`

where ,

• V is potential difference
• i is current
• R is resistance

`\implies 10V = i * 1.25\Omega \\`

`\implies i =(10)/(1.25) A \\`

`\implies \underline{\underline{ i = 8A }}\\`

and we are done!