Question

A hockey player hits a hockey puck sitting at rest and applies an average force of 440.0 N to the 0.15 kg

hockey puck for a time of 0.01 seconds. How fast does the puck go after the hit in m/s?

Answer 1

29.333

Step-by-step explanation:

This is a standard F=ma problem which then uses kinematics.

The 440 newtons is the force applied to the puck, the mass is the mass obviously. F+ma turns into A=F/m, A=440/.15 which equals 2933.333.

Vf=Vi+aT.

Vi=0, A=2933.333, T=.01

Vf = 29.333