Question

For a certain ideal gas, the temperature is

increased from 200 K to 602 K allowing pres-
sure, which is initially 1 atm, to vary while
the volume and number of moles of gas are
held constant. What is the new pressure?
Answer in units of atm.

Answer 1

3.01 atmospheres

Step by step explanation:

The pressure of an ideal gas is directly proportional to its temperature and directly inversely proportional to its volume. Since the volume and number of moles are held constant, the pressure will be directly proportional to the temperature.

So, using the ideal gas law, P1/T1 = P2/T2, where P1 and T1 are the initial pressure and temperature, respectively, and P2 and T2 are the new pressure and temperature, respectively.

Substituting the initial values, P1 = 1 atm and T1 = 200 K, and the new temperature T2 = 602 K, we can solve for P2:

P2 = (P1 x T2) / T1 = (1 atm x 602 K) / 200 K = 3.01 atm

Therefore, the new pressure is 3.01 atm.