Answer:
Second choice:

Explanation:
Consider the right triangle ABC
By the Pythagorean theorem,
AB² = BC² + AC²
BC = x, AC = (w + x) and AB = v
Plug in above values
(w + z)² = v² + x² (1)
In right triangle BCD,
BC² = BD² + CD²
Plugging in values we get
x² = w² + y² (2)
In right triangle ABD
AB² = BD² + AD²
v² = y² + z² (3)
Plug in values of x² from eq (2) and v² from eq 3 into equation (1) to get
(w + z)² = y² + z² +w² + y²
Left side (w + z)² = w² + 2wz + z²
==> w² + 2wz + z² = y² + z² +w² + y²
w² and z² cancel out since they are on both sides of the equation with same sign
=> 2wz = y²+y²
2wz = 2y²
Divide by 2:
wz = y²
Switch sides:
y² = wz
