Question

A string with a linear density of 2 kg/m and a tension of 100 N is fixed at both ends. Determine the frequency of the first harmonic of the string.

Answer 1

Explanation:

The frequency of the first harmonic of a string fixed at both ends can be calculated using the formula:

f = (1 / 2L) * (T / μ)^(1/2)

where:
f = frequency
L = length of the string
T = tension
μ = linear density of the string

Plugging in the values:
f = (1 / 2 * L) * (100 N / 2 kg/m)^(1/2)
f = (1 / 2L) * (10 N/kg)^(1/2)

We don't have the length of the string, L, so we can't calculate the frequency.

Answer 2

Explanation:

The frequency of the first harmonic of a string fixed at both ends can be determined using the formula:

f = (1 / 2L) * √(T / μ)

where f is the frequency, L is the length of the string, T is the tension, and μ is the linear mass density. Plugging in the given values:

f = (1 / 2 * L) * √(100 N / 2 kg/m)

= (1 / 2 * L) * √(50 N/m)

So, the frequency of the first harmonic depends on the length of the string, which is not specified in the problem.